t8cneyqgrt
Answered

Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

100 POINTS AND BRAINLIST

100 POINTS AND BRAINLIST class=

Sagot :

  • X=B

All ratios remains same

[tex]\\ \rm\hookrightarrow sinX=\dfrac{P}{H}=\dfrac{30.8}{34}=0.9[/tex]

[tex]\\ \rm\hookrightarrow cosX=\dfrac{B}{H}=\dfrac{14.4}{34.4}=0.42[/tex]

[tex]\\ \rm\hookrightarrow tanX=\dfrac{sinX}{cosX}=\dfrac{0.9}{0.42}=2.14[/tex]

fieryanswererft

Answer:

[tex]\sf tan(X) = 2.14[/tex]

[tex]\sf sin(X)= 0.91[/tex]

[tex]\sf cos(X)= 0.42[/tex]

Solve for tan(X):

[tex]\sf tan(x) = \dfrac{opposite}{adjacent}[/tex]

[tex]\sf tan(X) = \dfrac{30.8}{14.4}[/tex]

[tex]\sf tan(X) = 2.14[/tex]

Solve for sin(X):

[tex]\sf sin(x)= \dfrac{opposite}{hypotensue}[/tex]

[tex]\sf sin(X)= \dfrac{30.8}{34}[/tex]

[tex]\sf sin(X)= 0.91[/tex]

Solve for cos(X):

[tex]\sf cos(x)= \dfrac{adjacent}{hypotensue}[/tex]

[tex]\sf cos(X)= \dfrac{14.4}{34}[/tex]

[tex]\sf cos(X)= 0.42[/tex]

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.