At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

100 POINTS PLUS BRAINILY

100 POINTS PLUS BRAINILY class=

Sagot :

Answer:

[tex]\sf adjacent = 4.5 \ ft[/tex]

Explanation:

[tex]\sf tan(x) = \dfrac{opposite}{adjacent}[/tex]

[tex]\sf tan(71) = \dfrac{13}{adjacent}[/tex]

[tex]\sf adjacent = \dfrac{13}{tan(71)}[/tex]

[tex]\sf adjacent = 4.5 \ ft[/tex]

  • Perpendicular=P=13
  • Base=?

Let base be B

[tex]\\ \rm\hookrightarrow tan\theta=\dfrac{Perpendicular}{Base}[/tex]

[tex]\\ \rm\hookrightarrow tan71=\dfrac{13}{B}[/tex]

[tex]\\ \rm\hookrightarrow B=13/2.9[/tex]

[tex]\\ \rm\hookrightarrow B=4.48ft[/tex]