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Use the equation of sodium chloride dissolving in water to complete the activity.

NaCl(s) ⇄ Na+(aq) + Cl–(aq)

A student is testing two clear liquids. One liquid is water that has been modified to have a basic pH. The other liquid is a sports drink that contains added electrolytes, including Na+(aq). How can the student use the equilibrium reaction of sodium chloride to determine which liquid is which? In three to five sentences, explain your answer.

(Please someone let me know if they got it ^^)


Sagot :

Answer

If we add the sports drink and basic water to the "NaCl" solution, then the electrolytes will go left because we're adding more "Na+" and creating salt crystals. If we add basic water (which has "OH- ions"), it will go right because it uses "Na+" to form "NaOH." 

Explanation

Okay it finally let me answer it pff

If you're taking the Connexus unit test then I'm pretty sure the teacher is giving full points for it despite the answer

In the drink, if we add more Na which makes salt crystals, the electrolyte goes to the left.

If we add more OH- ions, that is water, it migrates towards the right.

What is sodium chloride?

Sodium chloride is a salt compound made of sodium metal and chlorine non-metal.

The reaction is

NaCl (s) ⇄ Na+(aq) + Cl–(aq)

According to Le Châtelier's principle, the solution in order to attain equilibrium changes.

In the drink, if we add more Na which makes salt crystals, the electrolyte goes to the left.

If we add more OH- ions, that is water, it migrates towards the right.

Thus., By Le Châtelier's principle, it can determine which liquid is which.

Learn more about sodium chloride

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