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Given: BD bisects AC and ∠CBE≅∠ADE.
Prove: ABCD is a parallelogram.

Given BD Bisects AC And CBEADE Prove ABCD Is A Parallelogram class=

Sagot :

Using supplementary angle theorem

  • <CDE=<ABE

As BD bisects AC

  • AE=EC
  • BE=ED

So ∆AEC[tex]\cong [/tex]∆DEC(SAS)

Also similarly

  • ∆BEC[tex]\cong [/tex]∆AED

Hence it's a parallelogram

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