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) If you prepared a solution by adding equal numbers of moles of sodium sulfite (Na2SO3) and sodium hydrogen sulfite (NaHSO3) to 50 mL of water, what would be the pH of the solution

Sagot :

okpalawalter8

The pH of the solution is mathematically given as

PH=7.21

What would be the pH of the solution?

Question Parameters:

sodium hydrogen sulfite (NaHSO3) to 50 mL of water.

Generally, the equation for the Chemical Reaction for the acid dissociation  is mathematically given as

HSO3- + H2O ---> H3O+ + SO3^2-

Therefore

[tex]pH=Pka+log\frac{A-}{Ha}[/tex]

A-=HA

pH=pKa

Since pKa NaHSO3=7.21

Hence, PH=7.21

For more information on Chemical Reaction

https://brainly.com/question/11231920

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