Answered

Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

As an airplane rises. the outside temperature drops from 3.6F for every 1000 feet of elevation gain. Suppose the outside temperature is 75F on the ground when the plane takes off and -51F at cruising altitude. How high is the plane then?


1. Write an equation

2.Solve using the equation

Sagot :

jp524

Answer:

35,000

Step-by-step explanation:

1. Find the difference between 75 and -51.

75 - (-51) = 75+51 = 126

2. Divide 126 by 3.6

126/3.6 = 35

3. Now what is the number 35? That is how much times the airplane has approached 1,000ft. So you have to multiply 35 and 1,000.

35 x 1,000 = 35,000.

4. Find the equation

([75 - x]/3.6) × 1,000, in which this case, x is the Fahrenheit the surroundings is in

a. Substitute x with -51.

b. The equation should follow the exact steps I mentioned earlier.

Hope this helps

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.