Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

The half-life of a radioactive kind of praseodymium is 17 minutes. If you start with 56 grams of it, how much will be left after 34 minutes? grams Submit


Sagot :

Answer:

14

Step-by-step explanation:

First, find out how many half-lives have passed. Divide the number of minutes by the length of a half-life. 34÷17=22 half-lives have passed. Now figure out how much praseodymium will be left after 2 half-lives have passed. Multiply the starting amount of praseodymium by 12 a total of 2 times. 56 x 1/2 x 1/2 = 14 That calculation could also be written with exponents:56x (1/2)^2=14 After 2 half-lives, the amount of praseodymium left will be 14 grams.

Assuming the half-life of a radioactive kind of praseodymium is 17 minutes.The amount that will be left after 34 minutes is 14g.

Final amount

Since 34 minutes is exactly 2 half-lives of 17 minutes.

Hence, remaining amount will then be:
Remaining amount= (1/2)×(1/2) = (1/2)² of the initial amount

Final amount:

Final amount = (1/2)² (56g)

Final amount=0.25 (56g)

Final amount = 14 g

Inconclusion  the half-life of a radioactive kind of praseodymium is 17 minutes.The amount that will be left after 34 minutes is 14g.

Learn more about final amount here:https://brainly.com/question/25109150

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.