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The half-life of a radioactive kind of praseodymium is 17 minutes. If you start with 56 grams of it, how much will be left after 34 minutes? grams Submit
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Sagot :

KassyCar

Answer:

14

Step-by-step explanation:

First, find out how many half-lives have passed. Divide the number of minutes by the length of a half-life. 34÷17=22 half-lives have passed. Now figure out how much praseodymium will be left after 2 half-lives have passed. Multiply the starting amount of praseodymium by 12 a total of 2 times. 56 x 1/2 x 1/2 = 14 That calculation could also be written with exponents:56x (1/2)^2=14 After 2 half-lives, the amount of praseodymium left will be 14 grams.

abiolataiwo2015

Assuming the half-life of a radioactive kind of praseodymium is 17 minutes.The amount that will be left after 34 minutes is 14g.

Final amount

Since 34 minutes is exactly 2 half-lives of 17 minutes.

Hence, remaining amount will then be:
Remaining amount= (1/2)×(1/2) = (1/2)² of the initial amount

Final amount:

Final amount = (1/2)² (56g)

Final amount=0.25 (56g)

Final amount = 14 g

Inconclusion  the half-life of a radioactive kind of praseodymium is 17 minutes.The amount that will be left after 34 minutes is 14g.

Learn more about final amount here:https://brainly.com/question/25109150

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