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Out of 150 150 offspring born to a gray, short fin fish crossed to a long finned, blue fish heterozygous for both traits, how many are expected to be blue with short fins

Sagot :

Out of 150 offsprings born to a gray, 38 offsprings are expected to be blue with short fins

How to determine the expected number of blue fish with short fins

To do this, we make use of the following representations

  • L represents long finned fish
  • l represents short finned fish
  • g represents the gray fish
  • b represents the blue fish

So, we have the following genotypes

Lg, Lb, lg, lb

In the above 4 genotypes, lb represent the blue fishes with short fins

So, the probability of selecting a blue fish with short fins is:

[tex]p = \frac 14[/tex]

In 150 offsprings, we have:

n = 150

So, the expected value is:

[tex]E(x) = np[/tex]

This gives

[tex]E(x) = 150 * \frac 14[/tex]

Evaluate the product

[tex]E(x) = 37.5[/tex]

Approximate

[tex]E(x) = 38[/tex]

Hence, 38 offsprings are expected to be blue with short fins

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