Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
Answer:
The expression for destructive interference in thin films allows to find the result for the smallest thickness of the films is:
t = 2.03 10⁻⁸ mm
Explanation:
Given parameters
Incident wavelength lamo = 535 nm
Refractive index of the film n = 1.32
To find
The minimum thickness for destructive interference
The interference phenomenon occurs when the path of two rays scattered by an obstacle have different optical paths. In the case of thin films we must take into account:
The reflected wave has a phase change of 180º when it goes from a medium with a lower refractive index to a medium with a higher index.
Inside the film medium the wavelength is modulated by the refractive index.
In the attachment we see an outline of these events and the expression for destructive interference remains.
2 n t = m λ₀
Where n is the refractive index, t the thickness of the film, λ₀ the wavelength in the vacuum and m an integer indicating the order of interference.
t =
The first destructive interference occurs for m = 1, let's calculate.
t =
t = 202.65 nm
Let's reduce this amount to millimeters.
t = 202.65 nm
t = 2,027 10⁻⁸ mm
In conclusion, using the expression for destructive interference in thin films we can find the result for the smallest thickness of the films is:
t = 2.03 10⁻⁸ mm
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.