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A chess master plays 15 games. In how many ways can these games result in 10 wins, 2 losses, and 3 draws?

Sagot :

facundo3141592

There are 30,030 different ways in which out of 15 games, the results are 10 wins, 2 loses, and 3 draws.

How many permutations are there?

The total number of permutations is given by the factorial of the total number of games (15) divided by the factorials of the numbers of each type of outcome (10 wins, 2 loses, 3 draws).

Then the number of permutations is given by:

[tex]P = \frac{15!}{10!*2!*3!} = \frac{15*14*13*12*11}{2*3*2} = 30,030[/tex]

So there are 30,030 different ways in which out of 15 games, the results are 10 wins, 2 loses, and 3 draws.

If you want to learn more about permutations, you can read:

https://brainly.com/question/1216161

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