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If a person takes 30 ml of vinegar a day and the molarity of the vinegar is 0. 84 m then how many grams of acetic acid (hc2h3o2 ) will be consumed?

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The mass of the acetic acid in grams, if a person takes 30 ml of vinegar daily, with a molarity of 0.84 M is 1.512 g.

What is Molarity?

molarity is the concentration of a substance in mol per dm³

From the question,

The number of moles contained in the 30 mL vinegar is

  • n = (0.84×30)/1000
  • n = 0.0252 mol.

the molar mass of vinegar is calculated below.

  • m.m of (HC₂H₃O₂) = [1+(12×2)+(1×3)+(16×2)]
  • m.m = (1+24+3+32]
  • m.m = 60 g/mol.

To calculate the mass of acetic acid, we use the formula below.

  • R.m = n×m.m............. Equation 1

Where

  • R.m = mass of acetic acid.

Substitute these values into equation 1

  • R.m = (0.0252×60)
  • R.m = 1.512 g.

Hence, The mass of the acetic acid is 1.512 g.

Learn more about molarity here: https://brainly.com/question/20383725

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