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Sagot :
The mass of the acetic acid in grams, if a person takes 30 ml of vinegar daily, with a molarity of 0.84 M is 1.512 g.
What is Molarity?
molarity is the concentration of a substance in mol per dm³
From the question,
The number of moles contained in the 30 mL vinegar is
- n = (0.84×30)/1000
- n = 0.0252 mol.
the molar mass of vinegar is calculated below.
- m.m of (HC₂H₃O₂) = [1+(12×2)+(1×3)+(16×2)]
- m.m = (1+24+3+32]
- m.m = 60 g/mol.
To calculate the mass of acetic acid, we use the formula below.
- R.m = n×m.m............. Equation 1
Where
- R.m = mass of acetic acid.
Substitute these values into equation 1
- R.m = (0.0252×60)
- R.m = 1.512 g.
Hence, The mass of the acetic acid is 1.512 g.
Learn more about molarity here: https://brainly.com/question/20383725
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