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Sagot :
Topic : Linear equations in two variables.
Given :
- 2x - y = 3 ––– (i)
- - x - y = 3 ––– (ii)
Solution :
Now,
(i) – (ii)
[tex]\qquad \sf \: { \dashrightarrow 2x - y - ( - x - y) = 3 - 3}
[/tex]
[tex]\qquad \sf \: { \dashrightarrow 2x - y + x + y) = 3 - 3}
[/tex]
[tex]\qquad \sf \: { \dashrightarrow 3x = 0}
[/tex]
[tex]\qquad \bf \: { \dashrightarrow x = 0}
[/tex]
Now, substituting the value of x in Eq (i) :
[tex]\qquad \sf \: { \dashrightarrow 2x - y = 3 }[/tex]
[tex]\qquad \sf \: { \dashrightarrow 2(0)- y = 3 }[/tex]
[tex]\qquad \sf \: { \dashrightarrow 0- y = 3 }[/tex]
[tex]\qquad \bf \: { \dashrightarrow y = - 3 }[/tex]
Therefore,
- The value of x = 0 and y = -3
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