Given the value of the area, the width of the rectangle whose length is 2 units more than twice its width is 4 units
Option A) 4 units is the correct answer.
A rectangle is simply a 2-dimensional shape which has opposite sides equal to each other and all four angles are right angles.
Area of a rectangle is expressed as;
A = l × w
Where l is length and w is width
Given the data in the question;
We substitute our given values into the expression above.
A = l × w
40 = (2w + 2) × w
w( 2w + 2 ) = 40
2w² + 2w = 40
2w² + 2w - 40 = 0
divide through by 2
w² + w - 20 = 0
Using the quadratic formula;
x = (-b±√(b² - 4ac)) / (2a)
a = 1
b = 1
c = -20
w = (-1±√(1² - ( 4× 1 × -20 ))) / (2×1)
w = (-1±√(1 + 80)) / (2)
w = (-1±√(81)) / 2
w = (-1 ± 9) / 2
Hence
w = (-1 + 9) / 2 or (-1 - 9) / 2
w = 8/2 or -10/2
w = 4 or -5
But the width the rectangle cannot be a negative number.
Given the value of the area, the width of the rectangle whose length is 2 units more than twice its width is 4 units
Option A) 4 units is the correct answer.
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