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C
\qquad m \angle AOC
m∠AOC
m, angle, A, O, C
is a straight angle.

m

A
O
B
=
8
x
+
5
1

\qquad m \angle AOB = 8x + 51^\circ
m∠AOB=8x+51

m, angle, A, O, B, equals, 8, x, plus, 51, degrees

m

B
O
C
=
6
x

2
5

\qquad m \angle BOC = 6x - 25^\circ
m∠BOC=6x−25

m, angle, B, O, C, equals, 6, x, minus, 25, degrees
Find
m

A
O
B
m\angle AOB
m∠AOB
m, angle, A, O, B
:

C Qquad M Angle AOC MAOC M Angle A O C Is A Straight Angle M A O B 8 X 5 1 Qquad M Angle AOB 8x 51circ MAOB8x51 M Angle A O B Equals 8 X Plus 51 Degrees M B O C class=

Sagot :

Answer:

  • m∠AOB=139°

Step-by-step explanation:

m∠AOB+m∠BOC=180°

m∠AOB=8x+51°

m∠BOC=6x-25°

~

[tex]\tt 8x+51+6x-25=180[/tex]

[tex]\tt 14x+26=180[/tex]

[tex]\tt 14x=180-26[/tex]

[tex]\tt \cfrac{14x}{14} =\cfrac{154}{14}[/tex]

[tex]\tt x=11[/tex]

m∠AOB:-

[tex]\tt 8(11)+51[/tex]

[tex]\tt =88+51[/tex]

[tex]\tt =139^{o}[/tex]

Therefore, m∠AOB=139°