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Sagot :
Answer:
a
Step-by-step explanation:
[tex]y\leq\frac{1}{2}x+2 \\\\1\leq \frac{1}{2}(0)+2\\\\1\leq 0+2\\\\1\leq 2[/tex]
This statement is true
Hope this helps!
The linear inequality represented by the graph is y ≤ 1/2x + 2
How to determine the inequality?
From the graph, we have the following highlights:
- The graph crosses the y-axis at c = 2
- The graph is a less than or equal to graph
Next, we calculate the slope (m) using:
[tex]m = \frac{y_2 -y_1}{x_2 -x_1}[/tex]
Using the points on the graph, we have:
[tex]m = \frac{4 -2}{4 -0}[/tex]
Evaluate
m = 1/2
The first highlight implies that the y-intercept is 2.
So, the linear inequality is:
y ≤ mx + c
This gives
y ≤ 1/2x + 2
Hence, the linear inequality represented by the graph is y ≤ 1/2x + 2
Read more about linear inequality at:
https://brainly.com/question/18881247
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