Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
Question: Quadrilateral GABE is a square. Assume that point A is the centre of the circle. If the circumference (perimeter of a circle) is 201 ft., find AE.
Solution:
πd = C
πd = 201
3.14(d) = 201
diameter = 64.01
radius is half of the diameter.
radius = 64.01/2
radius = 32
GA = 32
As its sqaure, all sides are equal
GA = AB = GE = EB = 32
using Pythagoras theorem:
32² + 32² = AE²
AE = √2048.8
AE = 45.3 ft
Answer:
Step-by-step explanation:
C = πd = 2πr
201 = 2*3.14*AB
AB = 201 / (2*3.14) = 32
AE is the diagonal of square ABEG
Using Pythagoras theorem,
AE^2 = AB^2 + BE^2 = 2*AB^2
AE^2 = 2*32^2
AE = sqrt(2*32^2)
= 45.255
= 45.3 ft
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.