Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

If you combine 390.0 mL of water at 25.00 ∘C and 100.0 mL of water at 95.00 ∘C, what is the final temperature of the mixture? Use 1.00 g/mL as the density of water.

Sagot :

103.0 mL because if u calculate the mL of water you realize
indrawboy

heat water 1 = heat water 2

mass of water = density x volume

because density = 1 g/ml then:

mass water 1 = 100 g

mass water 2= 390 g

Input the equation:

mcΔt 1 = mcΔt 2

100 . c . (95 - T) = 390 . c . (T - 25)

9500 - 100T = 390T - 9750

9500+9750 = 390T+100T

19250=490T

T=39.29 °C

Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.