georgiedehaas22
Answered

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I really need help quick
y = x² -4x

find values of x when y=2

with explanation please

Sagot :

fieryanswererft

Answer:

[tex]\sf x=2+\sqrt{6},\:x=2-\sqrt{6}[/tex]

Explanation:

[tex]\sf y = x^2 -4x[/tex]

given that y = 2

[tex]\sf x^2 -4x = 2[/tex]

[tex]\sf x^2 -4x -2 = 0[/tex]

using quadratic formula:

[tex]\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \ \ \ when \ ax^2 + bx + c = 0[/tex]

[tex]\rightarrow \sf x_{1,\:2}=\dfrac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\cdot \:1\cdot \left(-2\right)}}{2\cdot \:1}[/tex]

[tex]\rightarrow \sf x_1=\dfrac{-\left(-4\right)+2\sqrt{6}}{2\cdot \:1},\:x_2=\dfrac{-\left(-4\right)-2\sqrt{6}}{2\cdot \:1}[/tex]

[tex]\rightarrow \sf x=2+\sqrt{6},\:x=2-\sqrt{6}[/tex]

in decimals:

[tex]\rightarrow \sf x=4.45 , \ -0.45[/tex]

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