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Sagot :
Answer:
3x + 5y = 50
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
given
3x + 5y = 8 ( subtract 3x from both sides )
5y = - 3x + 8 ( divide terms by 5 )
y = - [tex]\frac{3}{5}[/tex] x + [tex]\frac{8}{5}[/tex] ← in slope- intercept form
with slope m = - [tex]\frac{3}{5}[/tex]
Parallel lines have equal slopes , then
y = - [tex]\frac{3}{5}[/tex] x + c ← is the partial equation
to fid c substitute (10, 4 ) into the partial equation
4 = - 6 + c ⇒ c = 4 + 6 = 10
y = - [tex]\frac{3}{5}[/tex] x + 10 ← equation of parallel line in slope- intercept form
multiply through by 5 to clear the fraction
5y = - 3x + 50 ( add 3x to both sides )
3x + 5y = 50 ← equation of parallel line in standard form
Solution:
Step-1: Convert the equation of the line into slope intercept form.
- 3x + 5y = 8
- => 5y = -3x + 8
- => y = -3x/5 + 8/5
In this case, the slope we obtained is -3/5, which is -0.6. Let's use point slope form to find the original equation.
Step-2: Use point slope form.
- y - y₁ = m(x - x₁)
- => y - 4 = -0.6(x - 10)
- => y - 4 = -0.6x + 6
- => y = -0.6x + 10
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