Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
The best estimate of the proportion of all women at this university who have a body temperature more than 2 standard deviations above the mean is 2.28%.
Since the sample is normally distributed and has a mean μ = 98.52 F and a standard deviation, σ = 0.727 F and we need to find the percentage of all womenat this university who have a body temperature more than 2 standards deviations above the mean.
The normal distribution
Since the sample is normally distributed, 50% of the sample is below the mean. We have 34% of the sample at 1 standard deviation away from the mean and 47¹/₂% at 2 standard deviations above the mean.
Percentage below 2 standard deviations away from mean
So, the percentage below 2 standard deviations from the mean is 50% + 47¹/₂% = 97¹/₂%.
Percentage above 2 standard deviations away from mean
So, the percentage above 2 standard deviations from the mean is 100% - 97¹/₂% = 2¹/₂% = 2.5 %
Since 2.28 % is the closest to 2.5 % from the options, the best estimate is 2.28 %.
So, the best estimate of the proportion of all women at this university who have a body temperature more than 2 standard deviations above the mean is 2.28%.
Learn more about normal distribution here:
https://brainly.com/question/25800303
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.