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A very flexible helium-filled balloon is released from the ground into the air at 20. ∘c. The initial volume of the balloon is 5. 00 l , and the pressure is 760. Mmhg. The balloon ascends to an altitude of 20 km , where the pressure is 76. 0 mmhg and the temperature is − 50. ∘c. What is the new volume, v2 , of the balloon in liters, assuming it doesn't break or leak?

Sagot :

jaquelinefvr

The new volume, v2, of the balloon in liters, assuming it doesn't break or leak, is 38.0546 L. To perform the calculation we will use the Boyle-Gay-Lussac law gas equation.

What is the Boyle-Gay-Lussac law?

It is shown that the volume of the gas is inversely proportional to its pressure, while its volume is directly proportional to its temperature and constant pressure.

  • P1 x V1/T1 = P2 x V2/T2

P1= Initial gas pressure

V1= Initial gas volume

P2= Final gas pressure

V2= Final volume of gas

T1= Initial gas temperature (Kelvin)

T2= Final gas temperature

Substituting the values ​​in the formula, we have:

  • 760 x 5 / 293 = 76 x v2 / 223
  • v2 = 38.0546 L

Find out more about gas equation here:

https://brainly.com/question/25736513

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