cheyannehatton
Answered

Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

The height of a rocket t seconds after launch is modeled by the function: f(t)=-16t^2+72t.

What is the maximum height of the rocket in feet?

Sagot :

reinhard10158

Step-by-step explanation:

the extreme values of a function happen at the zeros of the first derivation of that function.

f(t) = -16t² + 72t

f'(t) = -2×16t + 72 = -32t + 72

0 = -32t + 72

32t = 72

t = 72/32 = 2.25 seconds

f(2.25) = -16(2.25)² + 72×2.25 = -16×5.0625 + 72×2.25 =

= -81 + 162 = 81 ft

so, the rocket reaches its maximum height of 81 ft after 2.25 seconds of flight.

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.