LazySpherers
Answered

Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

If 16.4 grams of copper (II) bromide react with 22.7 grams of sodium chloride, how many grams of sodium bromide are formed?

If 164 Grams Of Copper II Bromide React With 227 Grams Of Sodium Chloride How Many Grams Of Sodium Bromide Are Formed class=

Sagot :

Oseni

The amount of sodium bromide that would be formed from the reaction will be 7.5524 grams

Stoichiometric calculation

Looking at the equation of the reaction:

[tex]CuBr_2 + 2NaCl --- > CuCl_2 + 2NaBr[/tex]

The mole ratio of CuBr2 and NaCl is 1:2.

Mole of 16.4 grams of CuBr2 = 16.4/223.37

                                                 = 0.0734 moles

Mole of 22.7 grams of NaCl = 22.7/58.44

                                                 = 0.3884 moles

Equivalent mole of NaCl = 0.1468 moles

Thus, NaCl is in excess while CuBr2 is limiting.

Mole ratio of CuBr2 and NaBr = 1:1

Mass of 0.0734 mole NaBr = 0.0734 x 102.894

                                              = 7.5524 grams

More on stoichiometric calculation can be found here: https://brainly.com/question/8062886

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.