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what is the solution of 25 > -3(4n-3)

Sagot :

naǫ
[tex]25> -3(4n-3) \\ 25> -12n+9 \\ 25-9 > -12n \\ 16 > -12n \\ \frac{16}{-12} < n \\ -\frac{4}{3} < n \\ -1\frac{1}{3}< n \\ \boxed{n >-1\frac{1}{3}}[/tex]
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