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Which can be the first step in finding the equation of the line that passes through the points (5, negative 4) and (negative 1, 8) in slope-intercept form?
Calculate StartFraction 8 minus (negative 4) Over negative 1 minus 5 EndFraction = StartFraction 12 Over negative 6 EndFraction = negative 2..
Calculate StartFraction negative 1 minus 5 Over 8 minus (negative 4) EndFraction = StartFraction negative 6 Over 12 EndFraction = negative one-half..
Find that the point at which the line intersects with the line y = 0 is (3, 0).
Find that the point at which the line intersects with the line x = y is (2, 2).

Sagot :

Answer:

Step-by-step explanation:

its A :)

Answer= y=2x+6

The slope-intercept form of an equation of a line: y=mx+b

m - slope

b - y-intercept

We have the points (5, -4) and (-1, 8). Substitute:

m= [tex]\frac{8-(-4)}{-1-5}[/tex] =[tex]\frac{12}{-6}[/tex] =-2

Put the value of the slope and the coordinates of the point (5, -4) to the equation of a line,

-4=-2(5)+b

=-10+b

6=b

y=2x+6