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A curling stone has a mass of 19.1 kg and a velocity of 3.0 m/s. What is the momentum of the curling stone?

Sagot :

Considering the definition of momentum, the momentum of the curling stone is 57.3 [tex]\frac{kgxm}{s}[/tex].

Definition of linear momentum

The linear momentum or quantity of movement is the magnitude that allows us to measure the capacity of a body in motion to exert a force on another that is in its path.

The linear momentum of a particle of mass m or body m moving with a speed v is defined as the product of the mass times the speed:

P = m×v

Where, as previously stated:

  • P is the moment.
  • m is the mass of the body.
  • v is the speed.

The standard units for moment are [tex]\frac{kgxm}{s}[/tex], and moment is always a vector quantity. Its direction and direction coincide with those of the velocity vector.

Momentum of the curling stone

In this case, you know:

  • P= ?
  • m= 19.1 kg
  • v= 3 [tex]\frac{m}{s}[/tex]

Replacing in the definition of momentum:

P = 19.1 kg ×3 [tex]\frac{m}{s}[/tex]

Solving:

P=57.3 [tex]\frac{kgxm}{s}[/tex]

Finally, the momentum of the curling stone is 57.3 [tex]\frac{kgxm}{s}[/tex].

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