The tower will work within next 11 miles inasmuch the drives moves through the road.
How to determine a distance inside a cellular phone tower
The maximum distance corresponds to the radius of the tower ([tex]r[/tex]), in kilometers, the east direction corresponds to the +x semiaxis and the north direction corresponds to the +y semiaxis. The angle and magnitude of the rest stop are found below:
[tex]l = \sqrt{5^{2}+12^{2}}[/tex]
[tex]l = 13[/tex]
[tex]\theta = \tan^{-1}\left(\frac{12}{5} \right)[/tex]
[tex]\theta \approx 67.380^{\circ}[/tex]
To determine distance within the cellular phone tower works we need to solve the following system of linear equations representing vector components:
[tex]5 + x = 20\cdot \cos \theta[/tex] (1)
[tex]12 = 20\cdot \sin \theta[/tex] (2)
By (2):
[tex]\theta = 36.869^{\circ}[/tex]
By (1):
[tex]x = 11[/tex]
The tower will work within next 11 miles inasmuch the drives moves through the road. [tex]\blacksquare[/tex]
To learn more triangles, we kindly invite to check this verified question: https://brainly.com/question/25813512
