Answered

Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

You wish to test the following claim ( Ha) at a significance level of α=0.02
H0:μ1=μ2
Ha:μ1≠μ2


You believe both populations are normally distributed, but you do not know the standard deviations for either. We will assume that the population variances are not equal.

You obtain a sample of size n1=16 with a mean of M1=66.2 and a standard deviation of SD1=10.6 from the first population. You obtain a sample of size n2=26 with a mean of M2=68.8 and a standard deviation of SD2=12.9 from the second population.

What is the test statistic for this sample? (Report answer accurate to three decimal places.)
test statistic =


What is the p-value for this sample? For this calculation, use the conservative under-estimate for the degrees of freedom. The degrees of freedom is the minimum of n1 - 1 and n2 - 1. (Report answer accurate to four decimal places.)

p-value =

Sagot :

Answer:

Since we assume the variances of the two populations are the same, we can use the pooled variance in the computation of the t-statistic:pooled variance (Sp^2) = (n1-1)s1^2 + (n2-1)*s2^2 / (n1 + n2 - 2) = (13-1)*19.4^2 + (19-1)*12.6^2 / (13 +19- 2) = 245.8Sp = 15.67t-calc = (mean1 - mean2)/ (Sp * sqrt(1/n1 + 1/n2)) = (83.6-72.9)/(15.67 * sqrt(1/13 + 1/19) = 1.897since this is a right tailed test, the p-value = P(t > 1.897) at n1 + n2 - 2 = 30 degrees of freedom = 0.0337so would not reject.

Step-by-step explanation:

mark me brainliest!!

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.