gaby372472
Answered

Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

The school drama club sold 2,400 tickets to a play and made $9,000 from the ticket sales. Student tickets,
X, were $3 and adult tickets, y, were $5.
Create a system of two equations to represent this situation.

Sagot :

Azailia

Hi!

Given:

  • total tickets = 2,400
  • total profit = 9,000
  • student tickets cost $3
  • adult tickets cost $5
  • x = student tickets
  • y = adult tickets

The first equation we can make can use the total number of tickets. The total number of tickets would be equal to the number of student tickets plus the number of adult tickets, correct? Therefore:

[tex]x+y=2400[/tex]

Now, the second one can use the profit and the price of each ticket. The number of student tickets multiplied by 3 (for the price) plus the number of adult tickets multiplied by 5 would be equal to the total profit. Hence:

[tex]3x+5y=9000[/tex]

Therefore, your system of equations is:

[tex]x+y=2400[/tex]

[tex]3x+5y=9000[/tex]

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.