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∠A and \angle B∠B are supplementary angles. If m\angle A=(2x+26)^{\circ}∠A=(2x+26)
∘
and m\angle B=(x+25)^{\circ}∠B=(x+25)
∘
, then find the measure of \angle B∠B

Sagot :

we know angles A and B are supplementary, thus their sum is 180°.

[tex]\stackrel{\measuredangle A}{(2x+26)}~~ + ~~\stackrel{\measuredangle B}{(x+25)}~~ = ~~180\implies 3x+51=180\implies 3x=129\\\\\\x=\cfrac{129}{3}\implies x=43~\hspace{10em}\stackrel{\measuredangle B = 43 + 25}{68}[/tex]

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