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24
,
Factor:
x²-9
A
(x + 3XX-3)
B
(x+3)2
с
(x-3)
(x+3)(x+3)


Sagot :

Answer:

(x-3)(x+3)

Step-by-step explanation:

We are given the expression [tex]\displaystyle \large{x^2-9}[/tex]:—

To factor this expression, we have a formula for it which is difference of two squares:—

[tex]\displaystyle \large{a^2-b^2=(a+b)(a-b)}[/tex]

You can also swap from [tex]\displaystyle \large{(a+b)(a-b)}[/tex] to [tex]\displaystyle \large{(a-b)(a+b)}[/tex] via multiplication property.

From the expression, factor using the formula above:—

[tex]\displaystyle \large{x^2-9=(x^2)-(3)^2}\\\displaystyle \large{x^2-9=(x-3)(x+3)}[/tex]

Therefore, the factored expression is:—

[tex]\displaystyle \large{\boxed{(x-3)(x+3)}}[/tex]

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