theunkown9
Answered

Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Sarah wants to swim across a 193 m river. Due to the current she is swept 67 m downriver from where she wanted to be. What is the length that she actually swam from start to where she ended? Round to the nearest tenth

Sagot :

Answer:

Step-by-step explanation:

Sarah swam the diagonal length of a right-angled triangle with sides of river width, 193m and how far she was swept downstream, 67m.

By Pythagorean Theorem, distance swam = sqrt(193^2+67^2)

= 204.3 m

Apply Pythagorean theorem

[tex]\\ \rm\rightarrowtail H^2=P^2+B^2[/tex]

[tex]\\ \rm\rightarrowtail H^2=193^2+67^2[/tex]

[tex]\\ \rm\rightarrowtail H^2=41738[/tex]

[tex]\\ \rm\rightarrowtail H=204ft[/tex](Approx)

View image Аноним
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.