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How do i answer this problem s2 + 18s = 47 and it being in integers

Sagot :

Answer:

[tex]s=-9\pm8\sqrt{2}[/tex]

Step-by-step explanation:

[tex]s^2+18s=47\\\\s^2+18s-47=0\\\\s=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\ \\s=\frac{-18\pm\sqrt{(18)^2-4(1)(-47)}}{2(1)}\\ \\s=\frac{-18\pm\sqrt{324+188}}{2}\\\\s=\frac{-18\pm\sqrt{512}}{2}\\\\s=\frac{-18\pm16\sqrt{2}}{2}\\ \\s=-9\pm8\sqrt{2}[/tex]

This is all assuming that your problem is a quadratic equation

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