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A 5 cm object is 18. 0 cm from a convex lens, which has a focal length of 10. 0 cm. What is the distance of the image from the lens? Round your answer to three significant figures. Cm What is the height of the image? Round your answer to three significant figures. Cm.

Sagot :

The distance of the image from the lens V=22.5cm and the height of the image h=6.25cm.

What will be the distance and the height of the image placed in front of the convex lens?

It is given that

Hieght of an object H = 5cm

Distance of an object =18cm

Focal lenght of lens = 10cm

As we know that the lens formula is given by

[tex]\dfrac{1}{f} =\dfrac{1}{v} +\dfrac{1}{u}[/tex]

[tex]\dfrac{1}{v} =\dfrac{1}{10} -\dfrac{1}{18}=\dfrac{8}{180}[/tex]

so now

[tex]v= \dfrac{180}{8} =22.5\ cm[/tex]

Now to find the height of the image

[tex]\rm magnification =\dfrac{v}{u} =\dfrac{-Image\ Hieght }{object\ height}[/tex]

[tex]\rm magnification =\dfrac{22.5}{18} =\dfrac{-x}{5}[/tex]

[tex]x=-6.25\ cm[/tex]

Thus the distance of the image from the lens is V=22.5cm and the height of the image h=6.25cm.

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