We are given with an equation in variable y and we need to solve for y . So , now let's start !!!
We are given with ;
[tex]{:\implies \quad \sf \dfrac{33}{2}+\dfrac{3y}{5}=\dfrac{7y}{10}+15}[/tex]
Take LCM on both sides :
[tex]{:\implies \quad \sf \dfrac{165+6y}{10}=\dfrac{7y+150}{10}}[/tex]
Multiplying both sides by 10 ;
[tex]{:\implies \quad \sf \cancel{10}\times \dfrac{165+6y}{\cancel{10}}=\cancel{10}\times \dfrac{7y+150}{\cancel{10}}}[/tex]
[tex]{:\implies \quad \sf 165+6y=7y+150}[/tex]
Can be further written as ;
[tex]{:\implies \quad \sf 7y+150=165+6y}[/tex]
Transposing 6y to LHS and 150 to RHS
[tex]{:\implies \quad \sf 7y-6y=165-150}[/tex]
[tex]{:\implies \quad \bf \therefore \quad \underline{\underline{y=15}}}[/tex]
