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Sagot :
for this problem becasue it says to use m for miles we will use m in place of x and we will use P (standing for price) in place of Y. for the first equation (Company A) the equation would be [tex]Y=110 + 0m[/tex] it is unneeded to add the +0m but i did so you can see it here and compare later. for the second equation (Company B) the equation would be [tex]Y=65+.6m[/tex] i left off the 0's in the 0.60 becasue they don't change the number as long as you pay attention to the decimal. for the next step you would set the 2 equations equal to eachother and solve to find after how many miles the price would be the same. [tex]110+0m=65+.6m \\ 110-65=.6m-0m \\ 45=.6m \\45/.6=m \\ 75=m \\ m=75[/tex] in the last step i used properties of equations to flip the sides to make it more freindly to look at. what this says is that after 75 miles Company B will charge the same as Company A (a flat rate of 110) and it would be cheeper to use Company B anytime before 75 miles while it would be cheeper to use Company A anytime after 75 miles. setting this up as an inequlity btw would make it look like this (i will also sove it) [tex]110+0m<65+.6m \\ 110-65<.6m \\ 45<.6 \\ 75
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