At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
for this problem becasue it says to use m for miles we will use m in place of x and we will use P (standing for price) in place of Y. for the first equation (Company A) the equation would be [tex]Y=110 + 0m[/tex] it is unneeded to add the +0m but i did so you can see it here and compare later. for the second equation (Company B) the equation would be [tex]Y=65+.6m[/tex] i left off the 0's in the 0.60 becasue they don't change the number as long as you pay attention to the decimal. for the next step you would set the 2 equations equal to eachother and solve to find after how many miles the price would be the same. [tex]110+0m=65+.6m \\ 110-65=.6m-0m \\ 45=.6m \\45/.6=m \\ 75=m \\ m=75[/tex] in the last step i used properties of equations to flip the sides to make it more freindly to look at. what this says is that after 75 miles Company B will charge the same as Company A (a flat rate of 110) and it would be cheeper to use Company B anytime before 75 miles while it would be cheeper to use Company A anytime after 75 miles. setting this up as an inequlity btw would make it look like this (i will also sove it) [tex]110+0m<65+.6m \\ 110-65<.6m \\ 45<.6 \\ 75
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.