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Sagot :
If you distribute the 2 on the left you end up with
6y-8=10
then add 8 to both sides
6y=18
then divide by 6 on both sides
y=3
and if you plug it back in it should equal 10
2((3)(3)-4)=10
10=10
6y-8=10
then add 8 to both sides
6y=18
then divide by 6 on both sides
y=3
and if you plug it back in it should equal 10
2((3)(3)-4)=10
10=10
[tex]2(3y-4)=10\ \ \ |divide\ both\ sides\ by\ 2\\\\\frac{2(3y-4)}{2}=\frac{10}{2}\\\\3y-4=5\ \ \ \ \ |add\ 4\ to\ both\ sides\\\\3y=9\ \ \ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{y=3}[/tex]
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