Answered

Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

At a sporting event, the price for 3 cheeseburgers and 2 cups of lemonade is $14 and the price for 2 cheeseburgers and 4 cups of lemonade is $12. How much does it cost for 1 cheeseburger and 2 cups of lemonade?

Sagot :

thisisbenmanley
c= the price of a cheeseburger and l = the price of a lemonade:

[tex]3c + 2l=14\\2c+4l=12[/tex]

Divide the second equation by -2 to begin the process of solving by elimination:

[tex]3c + 2l=14\\-1/2\ (2c+4l=12)\\\\3c+2l=14\\-c-2l=-6\\\\2c=8\\c=4[/tex]

Now that we have c, 4, we can plug it in to one of the equations to find l:

[tex]3c + 2l=14\\3(4)+2l=14\\12+2l=14\\2l=2\\l=1[/tex]

So, each cheeseburger is $4 and each lemonade is $1.  The final answer is:

1 cheeseburger and 2 cups of lemonade would cost $6.
14 dollars= 3 cheeseburger plus 2 cups of lemonade
14=3[4]+2[1]=14
1 cheeseburger= 4 dollars
1 lemonade= 1 dollars
12 dollars= 2cheeseburger plus 4 cups of lemonade

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.