rowie15
Answered

Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

One number is 4 less than 3 times a second number. If 3 more than two times the first number is decreased by two times the second, the result is 11. What are both numbers?

Sagot :

thisisbenmanley
The 1st number is x and the 2nd number is y:

x = 3y-4
3 + 2x - 2y = 11

The first equation says that x is equal to "3y - 4", so you can plug in "3y - 4" for x in the second equation:

3 + 2(3y - 4) - 2y = 11
3 + 6y - 8 - 2y = 11
-5 + 4y = 11
4y = 16
y = 4

Now that you have y, you can plug it into the 1st equation to get x:

x = 3y - 4
x = 3(4) - 4
x = 12 - 4
x = 8

So, the 1st number is 8 and the 2nd number is 4.
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.