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Can you please help me factor

x^2-9x+18=2x

I know you have to make it =0 so I get

x^2-7x+18=0

I need help finding the two terms that add to -9 and multiply to 18. Please help and explain



Sagot :

x^2 - 11x + 18 =0 <=> x^2 - 2x - 9x +18 = 0 <=> x(x-2) - 9(x-2) = 0 <=> (x-2)(x-9) = 0 => x -2 = 0 or x -9=0 => x=2 or x = 9.