Answer:
[tex]y=\frac{5}{6} x -5[/tex]
Step-by-step explanation:
Hi there!
We are given the points (6,0) and (0, -5), and we want to write the equation of the line containing those points in slope-intercept form
Slope-intercept form can be written as y=mx+b, where m is the slope and b is the y intercept
First, we need to find the slope of the line
The formula for the slope can be written as [tex]\frac{y_2-y_1}{x_2-x_1}[/tex], where [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] are points
We have everything we need to find the slope, but let's label the points to avoid confusion
[tex]x_1=6\\y_1=0\\x_2=0\\y_2=-5[/tex]
Now substitute these values into the formula
m=[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
m=[tex]\frac{-5-0}{0-6}[/tex]
Subtract
m=[tex]\frac{-5}{-6}[/tex]
Simplify
m=[tex]\frac{5}{6}[/tex]
The slope of the line is 5/6
Let's plug this value into the formula for the equation of the line in slope-intercept form.
We substitute 5/6 for m in y=mx+b:
y=[tex]\frac{5}{6}x+b[/tex]
Now we need to find b
As stated before, b is the y intercept, which is the value where the line hits the y axis. The value of x at the y intercept is 0.
One of the points we were given is actually the y intercept; that point is (0, -5); notice how the value of x in this point is 0
The value of b is the value of y in this point, which is -5 in this case.
Substitute -5 as b in the formula.
[tex]y=\frac{5}{6} x -5[/tex]
Hope this helps!
See more on this subject here (n.b. the answer uses a different way of solving): https://brainly.com/question/20891204
