Answered

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Solve for x please and round

Solve For X Please And Round class=

Sagot :

BasketballEinstein

Answer:

[tex]\displaystyle 74,4[/tex]

Step-by-step explanation:

[tex]\displaystyle \frac{x}{67} = cot\:42 \hookrightarrow 67cot\:42 = x \hookrightarrow 74,411038494... = x \\ \\ 74,4 ≈ x[/tex]

OR

[tex]\displaystyle \frac{67}{x} = tan\:42 \hookrightarrow xtan\:42 = 67 \hookrightarrow \frac{67}{tan\:47} = x \hookrightarrow 74,411038494... = x \\ \\ 74,4 ≈ x[/tex]

Information on trigonometric ratios

[tex]\displaystyle \frac{OPPOCITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOCITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOCITE} = csc\:θ \\ \frac{ADJACENT}{OPPOCITE} = cot\:θ[/tex]

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