Jessicaa503
Answered

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How do I solve this equation? 3|13-2t|=15

Sagot :

crisforp
/ 13 - 2t / = 15 ÷ 3 ;
/ 13 - 2t / = 5 ;
13 - 2t = + 5 or 13 - 2t = -5 ;
First equation, -2t = - 8; t = 4 ;
Second equation, -2t = - 18 ; t = 9 ;
The solutions are 4 and 9 .
ValyRemus
[tex]3 |13 - 2t | =15[/tex] ⇒ [tex]|13-2t| = 15\div3[/tex] ⇒ [tex]\boxed {|13-2t| = 5}[/tex]

[tex]\hbox {We have two equations : 1. } |13-2t|=5 [/tex] 
                                               [tex]2.|13-2t|=-5[/tex]

[tex]\hbox{The first: } [/tex] ⇒ [tex]13-2t=5[/tex] ⇒ [tex]2t=13-5[/tex] ⇒ [tex]2t=8[/tex] ⇒ [tex]\boxed {t=4}[/tex]

[tex]\hbox { The second: } 13-2t=-5[/tex] ⇒ [tex]2t=13-(-5)=18[/tex] ⇒ [tex]\boxed {t=9}[/tex]
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