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Suppose you are provided with a 35.83 g sample of potassium chlorate to perform this experiment. What is the mass of potassium chloride you expect to release upon heating?

Sagot :

okpalawalter8

For a 35.83 g sample of potassium chlorate,  the mass of potassium chloride is mathematically given as

M Kcl=21.62g

What is the mass of potassium chloride you expect to release upon heating?

Generally, the equation for the Chemical Reaction  is mathematically given as

2KClO_3----->2KCl+2O_2

Therefore

[tex]Mole of KCl=\frac{35.57}{122.55}[/tex]

Mole of KCl=0.29mol

Mass of Kcl=0.29*74.55

Mass of Kcl=21.62g

In conclusion, Mass of Kcl

M Kcl=21.62g

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