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Find the value of y and z

Find The Value Of Y And Z class=

Sagot :

DᴀʀᴋPᴀʀᴀᴅᴏx

[tex]\qquad\qquad\huge\underline{{\sf Answer}} \huge♨[/tex]

In the given figure, NQ acts as a diameter and since diameter subtends 90° at the arc of the circle, so we can conclude that ~

[tex]\qquad \sf  \dashrightarrow \:3y = 90 \degree[/tex]

[tex]\qquad \sf  \dashrightarrow \:y = 90 \degree \div 3[/tex]

[tex]\qquad \sf  \dashrightarrow \:y = 30 \degree [/tex]

Now, Let's use Angle sum property of Triangle to solve for z :

[tex]\qquad \sf  \dashrightarrow \:4z + 3y + 50 \degree = 180 \degree[/tex]

[tex]\qquad \sf  \dashrightarrow \:4z +90 \degree + 50 \degree = 180 \degree[/tex]

[tex]\qquad \sf  \dashrightarrow \:4z = 180 \degree - (50 \degree + 90\degree)[/tex]

[tex]\qquad \sf  \dashrightarrow \:4z = 180 \degree - (140\degree)[/tex]

[tex]\qquad \sf  \dashrightarrow \:4z = 40 \degree[/tex]

[tex]\qquad \sf  \dashrightarrow \:z = 40 \degree \div 4[/tex]

[tex]\qquad \sf  \dashrightarrow \:z = 10 \degree [/tex]

I hope you understood the procedure, you can ask me in comments if you have any doubts.

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