Answered

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The distance between the points (1,2) and (x,-1) is 5 units. Find the possible values of x​

Sagot :

Answer:

-3,5

Step-by-step explanation:

[tex]d = \sqrt{(x _{2} - x _1) {}^{2} + (y _{2} - y _{1} {} ) {}^{2} } [/tex]

[tex]5 = \sqrt{(x - 1) {}^{2} + ( - 1 - 2) {}^{2} } [/tex]

[tex]5 = \sqrt{(x - 1) {}^{2} + ( - 3) {}^{2} } [/tex]

[tex]25 = (x - 1) {}^{2} + 9[/tex]

[tex]16 = (x - 1) {}^{2} [/tex]

[tex]4 = x - 1[/tex]

[tex]x = 5[/tex]

Or

[tex] - 4 = x - 1[/tex]

[tex]x = - 3[/tex]

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