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[tex] \rm \frac{ {10}^5 }{ {e}^{ \sqrt{e} } } \left( \int^{1}_0 {e}^{ \sqrt[]{ {e}^{x} } } \: dx + 2 \int_{e}^{ {e}^{ \sqrt{e} } } ln( ln(x) ) \: dx\right) \\ [/tex]​

Sagot :

LammettHash

In the first integral, substitute [tex]x \to e^{\sqrt{e^x}}[/tex]:

[tex]\displaystyle I = \int_0^1 e^{\sqrt{e^x}} \, dx = 2 \int_e^{e^{\sqrt e}} \frac{dx}{\ln(x)}[/tex]

In the second integral, integrate by parts:

[tex]\displaystyle J = \int_e^{e^{\sqrt e}} \ln(\ln(x)) \, dx = \dfrac12 e^{\sqrt e} - \int_e^{e^{\sqrt e}} \frac{dx}{\ln(x)}[/tex]

It follows that

[tex]\dfrac{10^5}{e^{\sqrt e}}(I+2J) = \dfrac{10^5}{e^{\sqrt e}} \times e^{\sqrt e} = \boxed{10^5}[/tex]

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