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i need help i will give them 100 points.

I Need Help I Will Give Them 100 Points class=

Sagot :

Hello!

∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘  ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘

Slope Formula:

[tex]\bold{\displaystyle\frac{y_2-y_1}{x_2-x_1}}[/tex]

Where

[tex]\bold{y_2}[/tex]  is the y-coordinate of the second point

[tex]\bold{y_1}[/tex] is the y-coordinate of the first point

[tex]\bold{x_2}[/tex] is the x-coordinate of the second point

[tex]\bold{x_1}[/tex] is the x-coordinate of the first point

Check the First example:

[tex]\bf{y_2}[/tex] = 6

[tex]\bf{y_1}[/tex]= -2

[tex]\bf{x_2}[/tex]=3

[tex]\bf{x_1}[/tex] = -9

Plug in the Values

[tex]\bf{\displaystyle\frac{6-(-2)}{3-(-9)} }[/tex]

6-(-2) is the same as 6+2; same with 3-(-9)

[tex]\bf{\displaystyle\frac{6+2}{3+9}}[/tex]

Simplify:

[tex]\bf{\displaystyle\frac{8}{12}}[/tex]

Is the slope negative? Nope!

How about Option B?

[tex]\bf{\displaystyle\frac{7-9}{5-6}}[/tex]

[tex]\bf{\displaystyle\frac{-2}{-1}}[/tex]

Right now it seems like the slope's negative, huh? Well, wait for it...

[tex]\bf{2}[/tex]

Kaboom!

Please remember that

[tex]\bigstar^\circ[/tex] A negative number multiplied/divided by a negative number equals... a positive! :-)

We have 2 options left: C & D.

[tex]\displaystyle\frac{-8-1}{8-(-8)}[/tex]

[tex]\displaystyle\frac{-8-1}{8+8}}[/tex]

[tex]\displaystyle\frac{-9}{16}}[/tex]

We did it! The slope's actually negative :)

How about Option D (just to make sure the third option is right)

-9-(-8)/-1-2

-9+8/-3

-1/-3

Again we have a negative over a negative.

Therefore, the correct option is

[tex]\boxed{\boxed{\bold{Option~C}}}[/tex]

Hope everything is clear.

Let me know if you have any questions!

#LearnWithJoy

[tex]\text{An~Emotional~Helper}[/tex]

[tex]\rule{2}{2}~\rule{2}{2}~\rule{2}{2}~\rule{2}{2}~\rule{2}{2}~\rule{2}{2}[/tex]

the last one because the y is negative