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Sagot :
Hello!
∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘ ∘
Slope Formula:
[tex]\bold{\displaystyle\frac{y_2-y_1}{x_2-x_1}}[/tex]
Where
[tex]\bold{y_2}[/tex] is the y-coordinate of the second point
[tex]\bold{y_1}[/tex] is the y-coordinate of the first point
[tex]\bold{x_2}[/tex] is the x-coordinate of the second point
[tex]\bold{x_1}[/tex] is the x-coordinate of the first point
Check the First example:
[tex]\bf{y_2}[/tex] = 6
[tex]\bf{y_1}[/tex]= -2
[tex]\bf{x_2}[/tex]=3
[tex]\bf{x_1}[/tex] = -9
Plug in the Values
[tex]\bf{\displaystyle\frac{6-(-2)}{3-(-9)} }[/tex]
6-(-2) is the same as 6+2; same with 3-(-9)
[tex]\bf{\displaystyle\frac{6+2}{3+9}}[/tex]
Simplify:
[tex]\bf{\displaystyle\frac{8}{12}}[/tex]
Is the slope negative? Nope!
How about Option B?
[tex]\bf{\displaystyle\frac{7-9}{5-6}}[/tex]
[tex]\bf{\displaystyle\frac{-2}{-1}}[/tex]
Right now it seems like the slope's negative, huh? Well, wait for it...
[tex]\bf{2}[/tex]
Kaboom!
Please remember that
[tex]\bigstar^\circ[/tex] A negative number multiplied/divided by a negative number equals... a positive! :-)
We have 2 options left: C & D.
[tex]\displaystyle\frac{-8-1}{8-(-8)}[/tex]
[tex]\displaystyle\frac{-8-1}{8+8}}[/tex]
[tex]\displaystyle\frac{-9}{16}}[/tex]
We did it! The slope's actually negative :)
How about Option D (just to make sure the third option is right)
-9-(-8)/-1-2
-9+8/-3
-1/-3
Again we have a negative over a negative.
Therefore, the correct option is
[tex]\boxed{\boxed{\bold{Option~C}}}[/tex]
Hope everything is clear.
Let me know if you have any questions!
#LearnWithJoy
[tex]\text{An~Emotional~Helper}[/tex]
[tex]\rule{2}{2}~\rule{2}{2}~\rule{2}{2}~\rule{2}{2}~\rule{2}{2}~\rule{2}{2}[/tex]
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