samuelmeier187
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29. A pendulum with a period of 2.00000 s in one location (g=9.80m/s2) is moved to a new location where the period is now 1.99796 s. What is the acceleration due to gravity at its new location?

Please include all of your steps to the solution.

Sagot :

Answer:

9.82 m/s²

Explanation:

  • The time period of a pendulum, a body fixed to a pivot by means of a string, is given by the time it takes to complete a single cycle from right to left or left to right
  • The formula is given as :

        ⇒ T = 2π√(L/g) [← Important]

  • L represents the length of the string and g is the value of gravity due to acceleration

Original Time Period [To calculate length of the string]

  • T = 2π√(L/g)
  • 2 = 2π√(L/9.8)
  • L = 9.8/π²
  • L = 0.99646 m [← Keep in mind, we'll need it later!]

Calculating value of g' (new acceleration)

  • T = 2π√(L/g')
  • 1.99796 = 2π√0.99646/g' [← From earlier!]
  • g' = 9.82 m/s² (approximately)

Hope it helped~

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