Answered

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A globe has a diameter of 12 inches. It fits inside a cube-shaped box that has a side length of 12 inches.

​What is the volume, rounded to the nearest hundredth of a cubic inch, of the space inside the box that is not taken up by the globe?

Sagot :

The volume, rounded to the nearest hundredth of a cubic inch, of the space inside the box that is not taken up by the globe is 823.68 inches³

Volume of a sphere

The globe is a sphere. Therefore, the volume is as follows:

volume = 4 / 3 πr³

where

r = 12  /2 = 6 inches

volume = 4 / 3 × π × 6³

volume = 864 / 3 π

volume = 288 × 3.14  = 904.32inches³

Volume of a cube

The box is a cube. Therefore,

volume = L³

where

  • L = length

Therefore,

volume = 12³

volume = 1728 inches³

Therefore, the volume of the space inside the box that is not taken up by the globe is as follows:

volume not taken up = 1728 - 904.32 = 823.68 inches³

learn more on volume here: https://brainly.com/question/15385003

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